Theoretically, if the wildtype is D/d, A/a, M/m (recessive for leucistic, albino, and melanoid), and the Leucistic is d/d, A/a, M/m (leucistic, recessive for albino and melanoid), you could get Wildtype offspring (D/d, A/a, M/m), leucistic offspring (d/d, A/a, M/m), albino offspring (both white (d/d, a/a, M/m) and gold (D/d, a/a, M/m)), and melanoid offspring (albino (d/d (or D/d), a/a, m/m) and dark (D/d, A/a, m/m)).
But that's only if both of your axolotls are recessive for the traits. If the wildtype is D/D, A/A, M/M and the leucistic is d/d, A/A, M/M, you'll get only wildtype offspring which are recessive for leucistic (D/d, A/A, M/M).
In order to get anything other than wildtype offspring, both parents must be recessive for a gene, whether it's D, A, or M. If only one parent is recessive for a gene, the color trait won't be passed on. That is, if the wildtype is D/D, A/A, M/M, and the leucistic is d/d, A/a, M/m, you'll still only get wildtype babies, of which 25% will be recessive for albino and melanoid, and all will be recessive for leucistic.
However, for any trait which both parents are recessive, say the albino gene (Wildtype: D/D, A/a, M/M, Leucistic: d/d, A/a, M/M), you'll probably get offspring of that color (In this case: goldens, D/d, a/a, M/m). To get white albinos, the wildtype parent must also be recessive for Leucistic (Wildtype: D/d, A/a, M/M, Leucistic: d/d, A/a, M/M) which leads to some babies with the genotype d/d, a/a, M/M.
Thoroughly confused yet?